Comments on: Evolution::Rails -> Ruby -> Haskell http://rubynations.wordpress.com/2006/12/28/evolutionrails-ruby-haskell/ Ruminations on Ruby, Rails, and Software Development Tue, 02 Jan 2007 13:49:10 +0000 http://wordpress.com/ hourly 1 By: Keith Lancaster http://rubynations.wordpress.com/2006/12/28/evolutionrails-ruby-haskell/#comment-2 Keith Lancaster Tue, 02 Jan 2007 13:49:10 +0000 http://rubynations.wordpress.com/2006/12/28/evolutionrails-ruby-haskell/#comment-2 True, and thanks for pointing that out. I've moved the blog to http://rubynations.blogspot.com, and updated the article just a bit. I hope that it makes things a bit clearer. True, and thanks for pointing that out. I’ve moved the blog to http://rubynations.blogspot.com, and updated the article just a bit. I hope that it makes things a bit clearer.

]]> By: David House http://rubynations.wordpress.com/2006/12/28/evolutionrails-ruby-haskell/#comment-1 David House Tue, 02 Jan 2007 10:43:09 +0000 http://rubynations.wordpress.com/2006/12/28/evolutionrails-ruby-haskell/#comment-1 Just to point out that Haskell doesn't actually disaprove of your local variables, in case anyone got that impression. In fact, the let-construct is designed to introduce exactly that. To give a contrived example, here's a function in C++ and its translation to Haskell: <code>int foo(int i) { int j, k; j = i * 5; k = pow(j,2); return k + 1; } foo :: Int -> Int foo i = let j = i * 5 k = j ^ 2 in k + 1 </code> Just to point out that Haskell doesn’t actually disaprove of your local variables, in case anyone got that impression. In fact, the let-construct is designed to introduce exactly that. To give a contrived example, here’s a function in C++ and its translation to Haskell:

int foo(int i) {
int j, k;
j = i * 5;
k = pow(j,2);
return k + 1;
}

foo :: Int -> Int
foo i =
let j = i * 5
k = j ^ 2
in k + 1

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